Tarea 5_ Aplicaciones de Newton

18/6/2015 Tarea 5: Aplicaciones de Newton

https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=3637684 1/25

Tarea5:AplicacionesdeNewtonDue:8:00pmonFriday,June19,2015

Youwillreceivenocreditforitemsyoucompleteaftertheassignmentisdue.GradingPolicy

Item1

Threesledsarebeingpulledhorizontallyonfrictionlesshorizontaliceusinghorizontalropes.Thepullisofmagnitude180 .

PartA

Findtheaccelerationofthesystem.

Expressyouranswerwiththeappropriateunits.

ANSWER:

PartB

FindthetensioninropeA.


ANSWER:

PartC

FindthetensioninropeB.


ANSWER:

/

=

=



Item2

Oneproblemforhumanslivinginouterspaceisthattheyareapparentlyweightless.Onewayaroundthisproblemistodesignaspacestationthatspinsaboutitscenterataconstantrate.Thiscreates"artificialgravity"attheoutsiderimofthestation.

PartA

Ifthediameterofthespacestationis840 ,howmanyrevolutionsperminuteareneededforthe"artificialgravity"accelerationtobe ?

ANSWER:

PartB

IfthespacestationisawaitingareafortravelersgoingtoMars,itmightbedesirabletosimulatetheaccelerationduetogravityontheMartiansurface .Howmanyrevolutionsperminuteareneededinthiscase?

ANSWER:

Item3

Asmallcarwithmass0.720 travelsatconstantspeedontheinsideofatrackthatisaverticalcirclewithradius5.00thefollowingfigure.

=

N

NT

= " SFWNJO

N T

= " SFWNJO

LH

N



PartA

Ifthenormalforceexertedbythetrackonthecarwhenitisatthetopofthetrack(point )is6.00 ,whatisthenormalforceonthecarwhenitisatthebottomofthetrack(point )?


ANSWER:

Item4

First,launchthevideobelow.Youwillbeaskedtouseyourknowledgeofphysicstopredicttheoutcomeofanexperiment.Then,closethevideowindowandanswerthequestionsatright.Youcanwatchthevideoagainatanypoint.

PartA

Considerthevideodemonstrationthatyoujustwatched.Whichofthefollowingchangeswouldmakeitmorelikelyfortheballtohitboththewhitecanandthegreencan?

Youdidnotopenhintsforthispart.

ANSWER:

Item5

/

=

Rolltheballfaster.Useaballthatisheavierthantheoriginalball.Useaballthatislighterthantheoriginalball,butstillheavierthananemptycan.Rolltheballslower.Noneoftheabove



Ablockliesonaplaneraisedanangle fromthehorizontal.Threeforcesactupontheblock: ,theforceofgravity,thenormalforceand ,theforceoffriction.Thecoefficientoffrictionislargeenoughtopreventtheblockfrom

sliding.

PartA

Considercoordinatesystema,withthexaxisalongtheplane.Whichforcesliealongtheaxes?

ANSWER:

PartB

Whichforcesliealongtheaxesofthecoordinatesystemb,inwhichtheyaxisisvertical?

ANSWER:

J

X

O

G

only

only

only

and

and

and

and and

G

O

X

G

O

G

X

O

X

G

O

X



Usuallythebestadviceistochooseacoordinatesystemsothattheaccelerationofthesystemisdirectlyalongoneofthecoordinateaxes.Ifthesystemisn'taccelerating,thenyouarebetteroffchoosingthecoordinatesystemwiththemostvectorsalongthecoordinateaxes.Butnowyouaregoingtoignorethatadvice.Youwillfindthenormalforce, ,usingverticalcoordinatesystemb.Inthesecoordinatesyouwillfindthemagnitude appearinginboththexandyequations,eachmultipliedbyatrigonometricfunction.

PartC

Becausetheblockisnotmoving,thesumoftheycomponentsoftheforcesactingontheblockmustbezero.Findanexpressionforthesumoftheycomponentsoftheforcesactingontheblock,usingcoordinatesystemb.

Expressyouranswerintermsofsomeorallofthevariables , , ,and .


ANSWER:

PartD

Becausetheblockisnotmoving,thesumofthexcomponentsoftheforcesactingontheblockmustbezero.Findanexpressionforthesumofthexcomponentsoftheforcesactingontheblock,usingcoordinatesystemb.

Expressyouranswerintermsofsomeorallofthevariables , , ,and .


ANSWER:

only

only

only

and

and

and

and and

G

O

X

G

O

G

X

O

X

G

O

X

O

O

O

G

X

J

= 5

O

G

X

J

= 4



PartE

Tofindthemagnitudeofthenormalforce,youmustexpress intermsof since isanunknown.Usingtheequationsyoufoundinthetwopreviousparts,findanexpressionfor involving and butnot .


ANSWER:

Item6

Aloudspeakerofmass25.0 issuspendedadistanceof =1.60 belowtheceilingbytwocablesthatmakeequalangleswiththeceiling.Eachcablehasalengthof =3.90 .

PartA

Whatisthetension ineachofthecables?

Use9.80 forthemagnitudeoftheaccelerationduetogravity.


ANSWER:

Item7

O

X

G

O

X

J

G

=O

LH $ N

( N

NT

= /



LearningGoal:

Tounderstandhowtheforcesexertedonanobjectonaninclinedplaneaffecttheobjectsmotion.

Forthistutorial,usethePhETsimulationTheRamp.Thissimulationallowsyoutoplaceavarietyofobjectsonaninclinedrampandlookattheresultingforcesandmotion.

Startthesimulation.Whenyouclickthesimulationlink,youmaybeaskedwhethertorun,open,orsavethefile.Choosetorunoropenit.SelectanobjecttoplaceontherampbyclickingonanyobjectundertheChooseObjectsectionoftherightpanel.Tochangetherampangle,youcanadjusttheRampAnglesliderbarintherightpaneloryoucanclickontherampanddragitupordown.Toturnofffriction,youcanclickontheFrictionlessoptionthatisabovethePositionsetting.YoucanhavethepersonpushingontheobjectbysettinganAppliedForcethatisnonzero(youcantypeinavalueintheAppliedForceboxontheleft,dragthebigverticalsliderbartotheleftoftheparallelforcegraph,oryoucanclickanddragontheobject).Whilethesimulationisrunning,agraphshowstheparallelforces(i.e.,thecomponentsoftheforcesalongtheramp)asafunctionoftime.

Feelfreetoplayaroundwiththesimulation.Whenyouaredone,clickResetbeforebeginningPartA.

PartA

Thefirstthingyouwillinvestigateisstaticfriction.Theforceofstaticfrictionistheparallelforceexertedonastationaryobjectbytheramp.Thisforceisalwaysdirectedoppositethedirectiontheobjectwouldslideiftherewerenofriction.Selectthecrateastheobjectfortheramp.Then,slowlyincreasetherampangle.Theindividualforcesactingonthecrateareshown.Theylllooksomethinglikethis:



Watchwhathappenstotheforceoffriction(theredvectorinthepictureortheredplotinthegraph)beforethecratestartstoslidedowntheramp.

Astherampangleincreases,theforceofstaticfriction

ANSWER:

PartB

Thisquestionwillbeshownafteryoucompletepreviousquestion(s).

PartC


PartD


increases.remainsthesame.decreases.



PartE


PartF


PartG


PartH


PhETInteractiveSimulationsUniversityofColoradohttp://phet.colorado.edu

Item8

LearningGoal:

Tointroducecontactforces(normalandfrictionforces)andtounderstandthat,exceptforfrictionforcesundercertaincircumstances,theseforcesmustbedeterminedfrom:netForce=ma.

Twosolidobjectscannotoccupythesamespaceatthesametime.Indeed,whentheobjectstouch,theyexertrepulsivenormalforcesoneachother,aswellasfrictionalforcesthatresisttheirslippingrelativetoeachother.Thesecontactforcesarisefromacomplexinterplaybetweentheelectrostaticforcesbetweentheelectronsandionsintheobjectsandthelawsofquantummechanics.Astwosurfacesarepushedtogethertheseforcesincreaseexponentiallyoveranatomicdistancescale,easilybecomingstrongenoughtodistortthebulkmaterialintheobjectsiftheyapproachtooclose.Ineverydayexperience,contactforcesarelimitedbythedeformationoraccelerationoftheobjects,ratherthanbythefundamentalinteratomicforces.Hence,wecanconcludethefollowing:Themagnitudeofcontactforcesisdeterminedby ,thatis,bytheotherforceson,andaccelerationof,thecontactingbodies.Theonlyexceptionisthatthefrictionalforcescannotexceed (althoughtheycanbesmallerthanthisorevenzero).

Normalandfrictionforces

Twotypesofcontactforcesoperateintypicalmechanicsproblems,thenormalandfrictionalforces,usuallydesignatedby and (or ,orsomethingsimilar)respectively.Thesearethecomponentsoftheoverallcontactforce:perpendiculartoand paralleltotheplaneofcontact.

)

N*

* "

GSJD

*

"



Kineticfrictionwhensurfacesslide

Whenonesurfaceisslidingpasttheother,experimentsshowthreethingsaboutthefrictionforce(denoted ):

1. Thefrictionalforceopposestherelativemotionatthepointofcontact,2. isproportionaltothenormalforce,and3. theratioofthemagnitudeofthefrictionalforcetothatofthenormalforceisfairlyconstantoverawide

rangeofspeeds.

Theconstantofproportionalityiscalledthecoefficientofkineticfriction,oftendesignated .Aslongastheslidingcontinues,thefrictionalforceisthen

(validwhenthesurfacesslidebyeachother).

Staticfrictionwhensurfacesdon'tslide

Whenthereisnorelativemotionofthesurfaces,thefrictionalforcecanassumeanyvaluefromzerouptoamaximum,where isthecoefficientofstaticfriction.Invariably, islargerthan ,inagreementwiththeobservationthat

whenaforceislargeenoughthatsomethingbreakslooseandstartstoslide,itoftenaccelerates.

Thefrictionalforceforsurfaceswithnorelativemotionistherefore

(validwhenthecontactingsurfaceshavenorelativemotion).

Theactualmagnitudeanddirectionofthestaticfrictionforcearesuchthatit(togetherwithotherforcesontheobject)causestheobjecttoremainmotionlesswithrespecttothecontactingsurfaceaslongasthestaticfrictionforcerequireddoesnotexceed .Theequation isvalidonlywhenthesurfacesareonthevergeofsliding.

PartA

Whentwoobjectsslidebyoneanother,whichofthefollowingstatementsabouttheforceoffrictionbetweenthem,istrue?

ANSWER:

PartB

Whentwoobjectsareincontactwithnorelativemotion,whichofthefollowingstatementsaboutthefrictionalforcebetweenthem,istrue?

ANSWER:

"

L

"

L

N

L

*"

L

N

L

*N

T

N

T

N

T

N

L

*"

T

N

T

*N

T

*"

T

N

T

Thefrictionalforceisalwaysequalto .Thefrictionalforceisalwayslessthan .Thefrictionalforceisdeterminedbyotherforcesontheobjectssoitcanbeeitherequaltoorlessthan

.

*N

L

*N

L

*N

L



PartC

Whenaboardwithaboxonitisslowlytiltedtolargerandlargerangle,commonexperienceshowsthattheboxwillatsomepoint"breakloose"andstarttoacceleratedowntheboard.

Theboxbeginstoslideoncethecomponentofgravityactingparalleltotheboard justbeginstoexceedsthemaximumforceofstaticfriction.Whichofthefollowingisthemostgeneralexplanationforwhytheboxacceleratesdowntheboard?

ANSWER:

PartD

Consideraprobleminwhichacarofmass isonaroadtiltedatanangle .Thenormalforce

Selectthebestanswer.

ANSWER:

Item9

A8.40 blockofice,releasedfromrestatthetopofa1.46 longfrictionlessramp,slidesdownhill,reachingaspeedof2.63 atthebottom.

PartA

Thefrictionalforceisalwaysequalto .Thefrictionalforceisalwayslessthan .Thefrictionalforceisdeterminedbyotherforcesontheobjectssoitcanbeeitherequaltoorlessthan

.

*N

T

*N

T

*N

T

H

Theforceofkineticfrictionissmallerthanthatofmaximumstaticfriction,but remainsthesame.Oncetheboxismoving, issmallerthantheforceofmaximumstaticfrictionbutlargerthantheforceofkineticfriction.Oncetheboxismoving, islargerthantheforceofmaximumstaticfriction.Whentheboxisstationary, equalstheforceofstaticfriction,butoncetheboxstartsmoving,theslidingreducesthenormalforce,whichinturnreducesthefriction.

H

H

H

H

J

isfoundusing

* #

* #DPTJ

*

#

DPTJ

LH N

NT



Whatistheanglebetweentherampandthehorizontal?

ANSWER:

PartB

Whatwouldbethespeedoftheiceatthebottomifthemotionwereopposedbyaconstantfrictionforceof10.3paralleltothesurfaceoftheramp?

ANSWER:

Item10

LearningGoal:

TopracticeProblemSolvingStrategy5.1Newton'sFirstLaw:EquilibriumofaParticle.

Supposethatyouwanttomoveaheavyboxwithmass30.0 acrossacarpetedfloor.Youtrypushinghardononeoftheedges,buttheboxdoesnotmove.Supposethatyouarepushingagainsttheboxfromanangle30.0 abovehorizontalwithaforceofmagnitude240 .Whatisthemagnitudeofthefrictionforceactingonthebox?

ProblemSolvingStrategy:Newton'sfirstlaw:Equilibriumofaparticle

IDENTIFYtherelevantconcepts:YoumustuseNewtonsfirstlawforanyproblemthatinvolvesforcesactingonabodyinequilibrium.Iftheprobleminvolvesmorethanonebodyandthebodiesinteractwitheachother,youllalsoneedtouseNewtonsthirdlaw.Becertainthatyouidentifythetargetvariable(s).

SETUPtheproblemusingthefollowingsteps:

1. Drawasimplesketchofthephysicalsituation,showingdimensionsandangles.2. Drawafreebodydiagramforeachbodythatisinequilibrium.Inyourfreebodydiagram,includeonlyone

body.3. Onyourfreebodydiagram,drawaforcevectorforeachinteraction,andlabeleachforcewithasymbol

representingthemagnitudeoftheforce.Ifyouknowtheangleatwhichaforceisdirected,drawtheangleaccurately.

4. Donotshowinthefreebodydiagramanyforcesexertedbythebodyonanyotherbody.Includeonlyforcesthatactonthebody.

5. Chooseasetofcoordinateaxes,andincludetheminyourfreebodydiagram.(Ifthereismorethanonebodyintheproblem,chooseaxesforeachbodyseparately.)

EXECUTEthesolutionasfollows:

1. Findthecomponentsofeachforce.2. Setthealgebraicsumofallxcomponentsofforceequaltozero.Inaseparateequation,setthealgebraic

sumofallycomponentsequaltozero.3. Iftherearetwoormorebodies,repeatalloftheabovestepsforeachbody.Ifthebodiesinteractwitheach

other,useNewtonsthirdlawtorelatetheforcestheyexertoneachother.4. Makesurethatyouhaveasmanyindependentequationsasthenumberofunknownquantities.Then,

= ]

/

= 2 NT

LH

/



solvetheseequationstoobtainthetargetvariables.

EVALUATEyouranswer:Lookatyourresults,andaskwhethertheymakesense.Whentheresultisasymbolicexpressionorformula,trytocheckyourformulainspecialcasesforwhichyoucanguesswhattheresultsoughttobe.

IDENTIFYtherelevantconcepts

Sincetheboxsitsinafixedposition,itisinequilibriumandNewton'sfirstlawapplies.YouwillnotneedtouseNewton'sthirdlawtodeterminethemagnitudeofanyoftheforces.Thetargetvariableisthemagnitudeofthefrictionforce.

SETUPtheproblemusingthefollowingsteps

PartA

Theboxistheimportantobjectinthisproblem.Chooseacoordinatesystemthatwillsimplifyyourwork,andthendrawafreebodydiagramforthebox.Youshouldgenerallyalignthepositivexaxiswiththedirectioninwhichyourobjectofinterestismoving,orthedirectioninwhichitwouldmoveiftherewerenofriction.Ifthefiguredepictsthesituation,whichofthefollowingdescribesthecoordinatesystemthatyoushoulduse?

ANSWER:

PartB


EXECUTEthesolutionasfollows

Positivexaxistotheleft,positiveyaxisupwardPositivexaxistotheright,positiveyaxisupwardPositivexaxistotheleft,positiveyaxisdownwardPositivexaxistotheright,positiveyaxisdownward



PartC


EVALUATEyouranswer

PartD


Item11

Asmallmetalcylinderrestsonacircularturntablethatisrotatingataconstantrate,asillustratedinthediagram.

PartA

Whichofthefollowingsetsofvectorsbestdescribesthevelocity,acceleration,andnetforceactingonthecylinderatthepointindicatedinthediagram?




ANSWER:

PartB

Let bethedistancebetweenthecylinderandthecenteroftheturntable.Nowassumethatthecylinderismovedtoanewlocation fromthecenteroftheturntable.Whichofthefollowingstatementsaccuratelydescribethemotionofthecylinderatthenewlocation?

Checkallthatapply.


ANSWER:

abcde

Thespeedofthecylinderhasdecreased.Thespeedofthecylinderhasincreased.Themagnitudeoftheaccelerationofthecylinderhasdecreased.Themagnitudeoftheaccelerationofthecylinderhasincreased.Thespeedandtheaccelerationofthecylinderhavenotchanged.



Item12

Whenanobjectrestsonasurface,thereisalwaysaforceperpendiculartothesurfacewecallthisthenormalforce,denotedby .Thetwoquestionstotherightwillexplorethenormalforce.

PartA

Amanattemptstopickuphissuitcaseofweight bypullingstraightuponthehandle.However,heisunabletoliftthesuitcasefromthefloor.Whichstatementaboutthemagnitudeofthenormalforce actingonthesuitcaseistrueduringthetimethatthemanpullsupwardonthesuitcase?


ANSWER:

PartB

Nowassumethatthemanofweight istiredanddecidestositonhissuitcase.Whichstatementaboutthemagnitudeofthenormalforce actingonthesuitcaseistrueduringthetimethatthemanissittingonthesuitcase?

*

3

T

*

Themagnitudeofthenormalforceisequaltothemagnitudeoftheweightofthesuitcase.Themagnitudeofthenormalforceisequaltothemagnitudeoftheweightofthesuitcaseminusthemagnitudeoftheforceofthepull.Themagnitudeofthenormalforceisequaltothesumofthemagnitudeoftheforceofthepullandthemagnitudeofthesuitcase'sweight.Themagnitudeofthenormalforceisgreaterthanthemagnitudeoftheweightofthesuitcase.

3

N

*




ANSWER:

Item13

LearningGoal:

Tounderstandtherelationshipbetweenappliedforce,netforce,acceleration,andmassfor1dimensionalmotion.

Forthisproblem,usethePhETsimulationForcesin1DMotion.Thissimulationallowsyoutopushondifferentobjectswithacertainhorizontalforceandseetheresultingmotion.Youcancontrolthemassoftheobjectanditscoefficientoffriction.Whiletheobjectisbeingpushed,youcanseegraphsshowingtheforce,velocity,acceleration,and/orpositionasafunctionoftime.

Themagnitudeofthenormalforceisequaltothemagnitudeofthesuitcase'sweight.Themagnitudeofthenormalforceisequaltothemagnitudeofthesuitcase'sweightminusthemagnitudeoftheman'sweight.Themagnitudeofthenormalforceisequaltothesumofthemagnitudeoftheman'sweightandthemagnitudeofthesuitcase'sweight.Themagnitudeofthenormalforceislessthanthemagnitudeofthesuitcase'sweight.



Startthesimulation.Whenyouclickthesimulationlink,youmaybeaskedwhethertorun,open,orsavethefile.Choosetorunoropenit.

ClickonGraphAppliedForceifthegraphshowingforcesisntalreadyvisible.Adjusttheappliedforcebymovingthesliderbar(whichistotheleftoftheforcegraph)upordown.Youcanalsoadjusttheappliedforcebyeithertypinginavalueinthedigitaldisplayordraggingtheobjecttotheleftorright,butitisdifficulttomaintainaconstantforcethisway.ClickGo,andwatchtheresultingmotion.Youcanchoosedifferentobjectsusingthemenuontherightsideofthewindow,andyoucanalsoturnfrictionofforon.

Feelfreetoplayaroundwiththesimulation.Whenyouaredone,clickClearandturnofffrictionpriortobeginningPartA.

PartA

Choosethe200 filecabinet.Settheappliedforceto400 (totheright).Besurefrictionisturnedoff.Whatisthenetforceactingonthefilecabinet?

ANSWER:

PartB


LH /

Themagnitudeofthenetforceisgreaterthan400 ,directeddownwardandtotheright.Themagnitudeofthenetforceislessthan400 ,directedtotheright.Thenetforceiszero.Themagnitudeofthenetforceis400 ,directedtotheright.Themagnitudeofthenetforceisgreaterthan400 ,directedupwardandtotheright.

/

/

/

/



PartC


PartD


PartE


PartF


PartG


PartH


PartI


PhETInteractiveSimulationsUniversityofColoradohttp://phet.colorado.edu

Item14

LH



Askydiverofmass80.0 (includingparachute)jumpsoffaplaneandbeginsherdescent.

Throughoutthisproblemuse9.80 forthemagnitudeoftheaccelerationduetogravity.

PartA

Atthebeginningofherfall,doestheskydiverhaveanacceleration?


ANSWER:

PartB

Atsomepointduringherfreefall,theskydiverreachesherterminalspeed.Whatisthemagnitudeofthedragforceduetoairresistancethatactsontheskydiverwhenshehasreachedterminalspeed?

Expressyouranswerinnewtons.


ANSWER:

PartC

Foranobjectfallingthroughairatahighspeed ,thedragforceactingonitduetoairresistancecanbeexpressedas

,

wherethecoefficient dependsontheshapeandsizeofthefallingobjectandonthedensityofair.Forahumanbody,thenumericalvaluefor isabout0.250 .

Usingthisvaluefor ,whatistheterminalspeed oftheskydiver?

Expressyouanswerinmeterspersecond.


ANSWER:

LH

NT

Notheskydiverfallsatconstantspeed.Yesandheraccelerationisdirectedupward.Yesandheraccelerationisdirecteddownward.

ESBH

= ESBH

/

2

2

LHN

2

UFSNJOBM



PartD

Whentheskydiverdescendstoacertainheightfromtheground,shedeploysherparachutetoensureasafelanding.(Usuallytheparachuteisdeployedwhentheskydiverreachesanaltitudeofabout900 3000 .)Immediatelyafterdeployingtheparachute,doestheskydiverhaveanonzeroacceleration?


ANSWER:

PartE

Whentheparachuteisfullyopen,theeffectivedragcoefficientoftheskydiverplusparachuteincreasesto60.0.Whatisthedragforce actingontheskydiverimmediatelyaftershehasopenedtheparachute?

Expressyouranswerinnewtons.


ANSWER:

PartF

Whatistheterminalspeed oftheskydiverwhentheparachuteisopened?

Expressyouranswerinmeterspersecond.


ANSWER:

= 2UFSNJOBM

NT

N GU

Notheskydiverkeepsfallingatconstantspeed.Yesandheraccelerationisdirecteddownward.Yesandheraccelerationisdirectedupward.

LHN

ESBH

= ESBH

/

2

UFSNJOBM

= 2UFSNJOBM

NT



Item15

Asshowninthefigure,blockA(mass2.22 )restsonatabletop.Itisconnectedbyahorizontalcordpassingoveralight,frictionlesspulleytoahangingblockB(mass1.21 ).ThecoefficientofkineticfrictionbetweenblockAandthetabletopis0.201.

PartA

DrawthefreebodydiagramforblockA.

DrawtheforcevectorswiththeirtailsatthecenteroftheblockA.Thelocationandorientationofyourvectorswillbegraded.Theexactlengthofyourvectorswillnotbegradedbuttherelativelengthofonetotheotherwillbegraded.

ANSWER:

LH

LH



PartB

DrawthefreebodydiagramforblockB.

DrawtheforcevectorswiththeirtailsatthecenteroftheblockB.Thelocationandorientationofyourvectorswillbegraded.Theexactlengthofyourvectorswillnotbegradedbuttherelativelengthofonetotheotherwillbegraded.

ANSWER:

PartC

Aftertheblocksarereleasedfromrest,findthespeedofeachblockaftermoving2.90 .

ANSWER:

PartD

Aftertheblocksarereleasedfromrest,findthetensioninthecord.

ANSWER:

DN

= 2 NT

= /



Item16

A1113 caranda2090 pickuptruckapproachacurveontheexpresswaythathasaradiusof212 .

PartA

Atwhatangleshouldthehighwayengineerbankthiscurvesothatvehiclestravelingat70.6 cansafelyrounditregardlessoftheconditionoftheirtires?

ANSWER:

PartB

Shouldtheheavytruckgoslowerthanthelightercar?

ANSWER:

PartC

Asthecarandtruckroundthecurveat70.6 ,findthenormalforceonthecartothehighwaysurface.

ANSWER:

PartD

Asthecarandtruckroundthecurveat70.6 ,findthenormalforceonthetrucktothehighwaysurface.

ANSWER:

Item17

Aboxwithmass10.0 movesonarampthatisinclinedatanangleof55.0 abovethehorizontal.Thecoefficientofkineticfrictionbetweentheboxandtherampsurfaceis =0.300.Choosethe axisalongthesurfaceoftherampandthe axisperpendiculartothesurface.

LH LH N

NJI

= ]

yesno

NJI

= DBS

/

NJI

= USVDL

/

LH

N

'

4

5



PartA

Calculatethemagnitudeoftheaccelerationoftheboxifyoupushontheboxwithaconstantforce130.0 thatisparalleltotherampsurfaceanddirecteddowntheramp,movingtheboxdowntheramp.


ANSWER:

PartB

Calculatethemagnitudeoftheaccelerationoftheboxifyoupushontheboxwithaconstantforce130.0 thatisparalleltotherampsurfaceanddirecteduptheramp,movingtheboxuptheramp.


ANSWER:

ScoreSummary:Yourscoreonthisassignmentis0.0%.Youreceived0outofapossibletotalof100points.

/

=

/

=

Tarea 5_ Aplicaciones de Newton

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