16. simplificar funciones
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Transcript of 16. simplificar funciones
![Page 1: 16. simplificar funciones](https://reader036.fdocuments.mx/reader036/viewer/2022062523/5873d3211a28ab9d168b6983/html5/thumbnails/1.jpg)
Minimización de funciones Booleanas
• Métodos algebraicos
![Page 2: 16. simplificar funciones](https://reader036.fdocuments.mx/reader036/viewer/2022062523/5873d3211a28ab9d168b6983/html5/thumbnails/2.jpg)
F1 (B,C)= 1+B’+C
F1 (B,C)= 1
1.-Identidades
2.- Factorización
AB’ + AB = A(B’+B)= A3.- Propiedad Distributiva
X+YZ = (X+Y) (X+Z)X (Y+Z) = XY +XZ4.-Teorema del consenso
AB+A’C+BC = AB+A’C5.-Teorema de Dmorgan
(AB)’=A’+ B’ (A+B)’=A’ B’A+B =(A’ B’)’ AB =(A’+B’)’
AND OR
A A=A A + A=AA 0 =0 A + 0 = AA 1 =A A + 1 =1A A’ =0 A+A’ =1
![Page 3: 16. simplificar funciones](https://reader036.fdocuments.mx/reader036/viewer/2022062523/5873d3211a28ab9d168b6983/html5/thumbnails/3.jpg)
F2 (D,C)= DC’(0)
F2 (D,C)= 0
1.-Identidades
2.- Factorización
AB’ + AB = A(B’+B)= A3.- Propiedad Distributiva
X+YZ = (X+Y) (X+Z)X (Y+Z) = XY +XZ4.-Teorema del consenso
AB+A’C+BC = AB+A’C5.-Teorema de Dmorgan
(AB)’=A’+ B’ (A+B)’=A’ B’A+B =(A’ B’)’ AB =(A’+B’)’
AND OR
A A=A A + A=AA 0 =0 A + 0 = AA 1 =A A + 1 =1A A’ =0 A+A’ =1
![Page 4: 16. simplificar funciones](https://reader036.fdocuments.mx/reader036/viewer/2022062523/5873d3211a28ab9d168b6983/html5/thumbnails/4.jpg)
F3 (A, B) = A’+B+A
F3 (A, B) = 1
1.-Identidades
2.- Factorización
AB’ + AB = A(B’+B)= A3.- Propiedad Distributiva
X+YZ = (X+Y) (X+Z)X (Y+Z) = XY +XZ4.-Teorema del consenso
AB+A’C+BC = AB+A’C5.-Teorema de Dmorgan
(AB)’=A’+ B’ (A+B)’=A’ B’A+B =(A’ B’)’ AB =(A’+B’)’
AND OR
A A=A A + A=AA 0 =0 A + 0 = AA 1 =A A + 1 =1A A’ =0 A+A’ =1
![Page 5: 16. simplificar funciones](https://reader036.fdocuments.mx/reader036/viewer/2022062523/5873d3211a28ab9d168b6983/html5/thumbnails/5.jpg)
F4 (A,,B,C) = A+A’BC
F4 (A,,B,C)=(A+A’)(A+BC)
F4 (A,,B,C)=A+BC
1.-Identidades
2.- Factorización
AB’ + AB = A(B’+B)= A3.- Propiedad Distributiva
X+YZ = (X+Y) (X+Z)X (Y+Z) = XY +XZ4.-Teorema del consenso
AB+A’C+BC = AB+A’C5.-Teorema de Dmorgan
(AB)’=A’+ B’ (A+B)’=A’ B’A+B =(A’ B’)’ AB =(A’+B’)’
AND OR
A A=A A + A=AA 0 =0 A + 0 = AA 1 =A A + 1 =1A A’ =0 A+A’ =1
![Page 6: 16. simplificar funciones](https://reader036.fdocuments.mx/reader036/viewer/2022062523/5873d3211a28ab9d168b6983/html5/thumbnails/6.jpg)
F4 (A,,B,C) = A+A’BC
F4 (A,,B,C)=(A+A’)(A+BC)
F4 (A,,B,C)=A+BC
1.-Identidades
2.- Factorización
AB’ + AB = A(B’+B)= A3.- Propiedad Distributiva
X+YZ = (X+Y) (X+Z)X (Y+Z) = XY +XZ4.-Teorema del consenso
AB+A’C+BC = AB+A’C5.-Teorema de Dmorgan
(AB)’=A’+ B’ (A+B)’=A’ B’A+B =(A’ B’)’ AB =(A’+B’)’
AND OR
A A=A A + A=AA 0 =0 A + 0 = AA 1 =A A + 1 =1A A’ =0 A+A’ =1
![Page 7: 16. simplificar funciones](https://reader036.fdocuments.mx/reader036/viewer/2022062523/5873d3211a28ab9d168b6983/html5/thumbnails/7.jpg)
1.-Identidades
2.- Factorización
AB’ + AB = A(B’+B)= A3.- Propiedad Distributiva
X+YZ = (X+Y) (X+Z)X (Y+Z) = XY +XZ4.-Teorema del consenso
AB+A’C+BC = AB+A’C5.-Teorema de Dmorgan
(AB)’=A’+ B’ (A+B)’=A’ B’A+B =(A’ B’)’ AB =(A’+B’)’
AND OR
A A=A A + A=AA 0 =0 A + 0 = AA 1 =A A + 1 =1A A’ =0 A+A’ =1