Solución Taller-fundamentos de la programación-operaciones y ecuaciones

3.1 Actividades de apropiación del conocimiento (Conceptualización y Teorización).

1. Calcular

a) (–5) + (+4)= (-1) b) (+8) + (–6)= (+2)

c) (–3) + (–12)= (-15) d) (+234) + (+123)= (+357)

2. Efectuar las sumas siguientes:

a) (–7) + (–4) + (+2) + (+12) + (–3) + (–9) = [(-11) + (+14)] + (-12) = (+3)+(-12) = (-9)

b) (+2) + (–6) + (–5) + (+5) + (–9) + (+3) =(-4)+ (0) + [(-9) + (+3)] = (-4) + (-3) = (-7)

c) (–5) + (–4) + (+2) + (+8) + (–3) + (–1) =[(-9)+(+10)]+(-4) = (+1)+(-4) = (-3)

d) (+7) + (–3) + (–2) + (–6) + (+5) + (+8) =[ (+4)+(-8)]+(+13)=(-4) +(+13) =(+9)

e) (–3) + (+7) + (–4) + (+2) +(–10) + (+6) =[(+4)+(-2)]+(-4) = (+2) + (-4) = (-2)

3. Haciendo las operaciones, comprobar que se verifica la siguiente igualdad escribiendo si es falsa o verdadera:

[(+5) + (–2)] + (–6) = (+5) + [(–2) + (–6)]

(+3) + (-6) = (+5) + (-8)

(-3) = (-3)

4. Hallar:

a) [(+5) + (–3)] + [(–2) + (+6)] =(+2) + (+4) = (+6)

b) [(–4) + 7] + {(–3) + [(+8) + (–5)]} =(+3) + [(-3) + (+3)] = (+3) + (0) = (+3)

c) {[(+6) + (–3)] + (+4)} + [(–1) + (+7)] =[(+3) + (+4)] + (+6) = (+7) + (+6) = (+13)

5. Calcular:

a) (+23) – (–15) = (+23) + (+5) = (+28)b) (–12) – (–35) = (-12)+(+35) = (+23)

c) (+8) – (+12) = (+8)+(-12)= (-4)d) (–24) – (+15) = (-24)+(-15) = (-39)

6. Hallar:

a) [(–4) + (–3)] – (+2) =(-7)-(+2) = (-7)+(-2) = (-9)

b) [(+8) – (–2)] + (+6) =[(+8)+(+2)] + (+6) = (+10) + (+6) = (+16)

c) [(–5) + (–2)] – (–6) =(-7) – (-6) = (-7) + (+6) = (-1)

d) [(+6) + (–2)] + (–5) =(+4)+(-5) = (-1)

e) [(–5) + (+9)] – (+6) =(+4)-(+6) = (+4)+(-6) = (-2)

3.2 Actividades de transferencia del conocimiento.

Resolución de Ecuaciones

1. 2x + 5 = 1 = x = (-2) 2. 3x = 21 = x= (+7)

3. 3x + 5 = 4x - 7 = x = (-12) 4. 3(x - 5) = 2(x + 2)=x = 19

5. x = 27 x = 243 6. 3 x = 6 = x = 10 9 5

7. x + 3 = x - 1 =x = -11 8. x + 9 = 2= x = 1 2 3 5

9. De: despeje t.t= Vo+- Vo2 + ad/2

10. De: halle el valor de Vo, sabiendo que Vf= 34, a=5 y d=7

Vo = 1086

11. De halle el valor de l, sabiendo que = al valor de Pi y g =6,98 y T=0,5

L = 0.0442