UNIVERSIDAD DE CARABOBO

FACULTAD DE INGENIERA

ESCUELA DE INGENIERA QUMICA

SIMULACIN DE PROCESOS QUMICOS

ASIGNACIN 1

Prof.: Katiuska Franceschi Realizado por:

ANAYA, Jess

NOGUERA, Arley

Seccin 65

Valencia, 05 de diciembre de 2013

PARTE 1. SIMULACIN CON EL PROGRAMA SIMEST

En la Figura 1 se muestra un diagrama de proceso de una planta qumica, donde se

encuentran presentes tres componentes RCA-201, DPU-012 y DPU-200 Figura 1.

Fig. 1. Diagrama del proceso.

Al equipo 1 es alimentado 1000gmol/h de RCA-201con una temperatura de 100C,

una presin de 3atm y una entalpa de 3,05E05 cal/gmol, en el tanque se encuentra

almacenado el DPU-012, y en la tubera 5 circula 1500 gmol/h a 25C a presin ambiente y

una entalpa de 2,46E05 cal/gmol. En el equipo 6 es alimentado 1000gmol/h de una

corriente de un sub producto de la empresa que contiene 55% de DPU-012 y 45% de DPU-

200 a una temperatura de 150C, una presin de 3,5atm y una entalpa de 1,06E06

cal/gmol.

En el equipo 1 es necesario garantizar que se opere a 3atm, por lo cual fue instalada

una bomba, la cual logra garantizar esta presin.

De igual manera es necesario que ambas alimentaciones del equipo 3 se encuentren

a

150C, por lo cual fueron instalados intercambiador es de calor.

De respuesta a las siguientes interrogantes formuladas:

1. El equipo de ingenieros quiere validar la operatividad de los intercambiadores

de calor. Determine cmo es el comportamiento de las temperaturas de las

entradas del equipo 3 si los intercambiadores no se encuentran operativos,

considere que los equipos 1, 3, 6 y 4 se pueden simular con el mezclador tipo 1.

Se necesitaran de calentadores o enfriadores?

Empleando el simulador SIMEST, se determin el comportamiento del sistema

original y se observ que las temperaturas de las corrientes de entrada al equipo 3, fue de

150C, como se esperaba. Se asumieron mezcladores tipo 1 y convergencia natural. Se

realiz la modificacin respectiva para determinar qu tanto variaba la respuesta del sistema

sin la presencia de los intercambiadores de calor. Se obtuvo que las temperaturas de las

corrientes de entrada al equipo 3 cuando no se tienen los intercambiadores de calor son

inferiores a la temperatura requerida por el sistema, por lo que se necesitaran calentadores

para llevar la temperatura hasta 150C. Los resultados se encuentran en la Tabla 1. Para el

sistema sin intercambiadores se renombraron algunas corrientes, por lo que el sistema

obtenido sin estos equipos es el representado en la Fig. 2.

Fig. 2. Sistema modificado (sin intercambiadores de calor).

Tabla 1. Temperaturas a la entrada del equipo 3 con y sin intercambiadores de calor.

Corriente Con Intercambiadores Sin intercambiadores

Proveniente del equipo 1 73,052 C 150,000 C

Proveniente del equipo 4 73,809 C 150,000 C

En la Tabla 2, se muestran las estructuras de los archivos DATOS.txt que se utilizaron

para la simulacin en SIMEST.

Tabla 2. Estructuras de los archivos DATOS.txt correspondientes a cada caso en

particular.

Con Intercambiadores Sin intercambiadores

ASIGNACION 1

1,1,1,1,1,1,0,0,0,0

0

9,3

7,8,1,4,2,5,3,6,9

15

1,7,7,7,1,7,7,7,7,7

3,7,2,1,3

3

1.,3.05E5,1000.,100.,3.

1000.,0.,0.

5.,2.46E5,1500.,25.,1.

0.,1500.,0.

14.,1.06E6,1000.,150.,3.5

0.,550.,450.

9

7.,1.,19.,0.,0.

1.,5.,0.,0.,0.

2.,6.,7.,0.,0.

ASIGNACION 1

1,1,1,1,1,1,0,0,0,0

0

7,3

7,8,1,4,3,6,9

13

1,7,3,7,1,7,7,7,7,7

1,3,2

3

1.,3.05E5,1000.,100.,3.

1000.,0.,0.

5.,2.46E5,1500.,25.,1.

0.,1500.,0.

11.,1.06E6,1000.,150.,3.5

0.,550.,450.

7

7.,1.,19.,0.,0.

1.,5.,0.,0.,0.

2.,6.,7.,0.,0.

0.5,0.5,0.,0.

8.,5.,16.,0.,0.

1.,7.,0.,0.,0.

1.,8.,0.,0.,0.

3.

1.,2.,33.,0.,0.

2.,1.,8.,0.,0.

2.,2.,4.,0.,0.

0.70,0.30,0.,0.,0.

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

4.,2.,33.,0.,0.

3.,4.,6.,13.,0.

1.,9.,0.,0.,0.

1.,0.,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

2.,4.,16.,0.,0.

1.,2.,0.,0.,0.

1.,3.,0.,0.,0.

150.

5.,4.,16.,0.,0.

1.,9.,0.,0.,0.

1.,10.,0.,0.,0.

150.

3.,2.,33.,0.,0.

2.,3.,10.,0.,0.

2.,11.,12.,0.,0.

0.40,0.60,0.,0.,0

0.5,0.5,0.,0.

8.,5.,16.,0.,0.

1.,7.,0.,0.,0.

1.,8.,0.,0.,0.

3.

1.,2.,33.,0.,0.

2.,1.,8.,0.,0.

2.,2.,4.,0.,0.

0.70,0.30,0.,0.,0.

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

4.,2.,33.,0.,0.

3.,4.,6.,13.,0.

1.,9.,0.,0.,0.

1.,0.,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

3.,2.,33.,0.,0.

2.,2.,9.,0.,0.

2.,3.,10.,0.,0.

0.40,0.60,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

6.,2.,33.,0.,0.

2.,10.,11.,0.,0.

2.,12.,13.,0.,0.

0.60,0.40,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

6.,2.,33.,0.,0.

2.,12.,14.,0.,0.

2.,13.,15.,0.,0.

0.40,0.60,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

9.,8.,28.,0.,1.

0.,0.,0.,0.,0.

0.,0.,0.,0.,0.

8.,100.,13.,0.00001,1.

1.,0.,0.,0.,0.

0.,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

9.,8.,28.,0.,1.

0.,0.,0.,0.,0.

0.,0.,0.,0.,0.

6.,100.,13.,0.00001,1.

1.,0.,0.,0.,0.

0.,0.,0.

2. Diferencia obtenida al simular los equipos 1, 3, 6 y 4 como mezclador tipo 1 y

como mezclador tipo 2.

Al intercambiar los mezcladores tipo 1 por tipo 2, se obtuvieron discrepancias

notorias en los resultados de las simulaciones en las corrientes de salida de cada mezclador,

tanto en entalpa, temperatura y presin, como puede evidenciarse en la Tabla 3, lo que indica

que el modelo matemtico que representa el comportamiento dinmico de la cada tipo de

mezclador toma diferentes consideraciones para los balances de energa. Los flujos molares

se mantienen idnticos, as como las fracciones de separacin. Se consideraron los

intercambiadores de calor y convergencia natural para ambas simulaciones.

Tabla 3. Comparacin entre los parmetros de cada corriente correspondientes a

cada unidad.

Unidad

Variable

Mezclador

Tipo 1 Tipo 2

1

Entalpa (cal/gmol) 0.29960E+06 0.13160E+07

Temperatura (C) 0.73052E+02 0.72876E+02

Presin (atm) 0.30000E+01 0.00000E+00

3

Entalpa (cal/gmol) 0.51316E+06 0.46141E+07

Temperatura (C) 0.15000E+03 0.15000E+03

Presin (atm) 0.30000E+01 0.00000E+00

4

Entalpa (cal/gmol) 0.98329E+06 0.44562E+07

Temperatura (C) 0.10185E+03 0.10117E+03

Presin (atm) 0.30000E+01 0.00000E+00

6

Entalpa (cal/gmol) 0.73189E+06 0.40101E+07

Temperatura (C) 0.15000E+03 0.15000E+03

Presin (atm) 0.30000E+01 0.00000E+00

Con el mezclador tipo 2, se observan presiones por debajo de la presin ambiente (1

atm), lo cual podra interpretarse como que dichos mezcladores son presurizados. En la Tabla

4, se muestran las estructuras de los archivos DATOS.txt que se utilizaron para la simulacin

en SIMEST.

Tabla 4. Estructuras de los archivos DATOS.txt correspondientes a cada caso en

particular.

Mezcladores Tipo 1 Mezcladores Tipo 2

ASIGNACION 1

1,1,1,1,1,1,0,0,0,0

0

9,3

7,8,1,4,2,5,3,6,9

ASIGNACION 1

1,1,1,1,1,1,0,0,0,0

0

9,3

7,8,1,4,2,5,3,6,9

15

1,7,7,7,1,7,7,7,7,7

3,7,2,1,3

3

1.,3.05E5,1000.,100.,3.

1000.,0.,0.

5.,2.46E5,1500.,25.,1.

0.,1500.,0.

14.,1.06E6,1000.,150.,3.5

0.,550.,450.

9

7.,1.,19.,0.,0.

1.,5.,0.,0.,0.

2.,6.,7.,0.,0.

0.5,0.5,0.,0.

8.,5.,16.,0.,0.

1.,7.,0.,0.,0.

1.,8.,0.,0.,0.

3.

1.,2.,33.,0.,0.

2.,1.,8.,0.,0.

2.,2.,4.,0.,0.

0.70,0.30,0.,0.,0.

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

4.,2.,33.,0.,0.

3.,4.,6.,13.,0.

1.,9.,0.,0.,0.

1.,0.,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

15

1,7,7,7,1,7,7,7,7,7

3,7,2,1,3

3

1.,3.05E5,1000.,100.,3.

1000.,0.,0.

5.,2.46E5,1500.,25.,1.

0.,1500.,0.

14.,1.06E6,1000.,150.,3.5

0.,550.,450.

9

7.,1.,19.,0.,0.

1.,5.,0.,0.,0.

2.,6.,7.,0.,0.

0.5,0.5,0.,0.

8.,5.,16.,0.,0.

1.,7.,0.,0.,0.

1.,8.,0.,0.,0.

3.

1.,3.,33.,0.,0.

2.,1.,8.,0.,0.

2.,2.,4.,0.,0.

0.70,0.30,0.,0.,0.

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

4.,3.,33.,0.,0.

3.,4.,6.,13.,0.

1.,9.,0.,0.,0.

1.,0.,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

2.,4.,16.,0.,0.

1.,2.,0.,0.,0.

1.,3.,0.,0.,0.

150.

5.,4.,16.,0.,0.

1.,9.,0.,0.,0.

1.,10.,0.,0.,0.

150.

3.,2.,33.,0.,0.

2.,3.,10.,0.,0.

2.,11.,12.,0.,0.

0.40,0.60,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

6.,2.,33.,0.,0.

2.,12.,14.,0.,0.

2.,13.,15.,0.,0.

0.40,0.60,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

9.,8.,28.,0.,1.

0.,0.,0.,0.,0.

0.,0.,0.,0.,0.

8.,100.,13.,0.00001,1.

1.,0.,0.,0.,0.

0.,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

2.,4.,16.,0.,0.

1.,2.,0.,0.,0.

1.,3.,0.,0.,0.

150.

5.,4.,16.,0.,0.

1.,9.,0.,0.,0.

1.,10.,0.,0.,0.

150.

3.,3.,33.,0.,0.

2.,3.,10.,0.,0.

2.,11.,12.,0.,0.

0.40,0.60,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

6.,3.,33.,0.,0.

2.,12.,14.,0.,0.

2.,13.,15.,0.,0.

0.40,0.60,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

9.,8.,28.,0.,1.

0.,0.,0.,0.,0.

0.,0.,0.,0.,0.

8.,100.,13.,0.00001,1.

1.,0.,0.,0.,0.

0.,0.,0.

3. Identifique las corrientes involucradas en el reciclo y determine la diferencia al

controlar cada una de ellas, adicionalmente se desea conocer cul es el efecto de

vigilar una corriente ajena al reciclo.

Las corrientes que forman parte del reciclo son la 9, 10, 12 y 13. Al hacer que el

controlador vigilara diferentes corrientes del sistema, se pudo observar que el nmero de

iteraciones variaba considerablemente entre las corrientes del reciclo y una ajena a este. Entre

las del reciclo, el nmero de iteraciones fue el mismo para las corrientes 9, 10 y 12, (10

iteraciones) y 9 iteraciones para la corriente 13, mientras que al vigilar la corriente 6, se

obtuvo la convergencia del controlador en la segunda iteracin. De igual manera, para las

corrientes involucradas en el reciclo, se obtuvieron idnticos resultados independientemente

de la corriente que vigilara el controlador, caso contrario que si se vigilaba una corriente

ajena (corriente 6), donde los valores resultaron ligeramente diferentes con respecto a los

anteriores. En la corriente ajena al proceso, los valores no variaron con respecto a los

iniciales, por lo que la fraccin de error fue de 0.00000E+00. En cambio, para las corrientes

pertenecientes al reciclo, se obtuvieron valores muy bajos, lo cual indicaba una gran exactitud

y precisin en los resultados.

Tabla 5. Variacin de los parmetros de las corrientes vigiladas por el controlador en

cada caso.

Corriente Variable Valor Fraccin

6

Entalpa (cal/gmol) 0.12300E+06 0.00000E+00

Flujo molar total (gmol/h) 0.75000E+03 0.00000E+00

Temperatura (C) 0.25000E+02 0.00000E+00

Presin (atm) 0.10000E+01 0.00000E+00

Flujo molar A (gmol/h) 0.00000E+00 0.00000E+00

Flujo molar B (gmol/h) 0.75000E+03 0.00000E+00

Flujo molar C (gmol/h) 0.00000E+00 0.00000E+00

9

Entalpa (cal/gmol) 0.98329E+06 0.62291E-05

Flujo molar total (gmol/h) 0.25908E+04 0.42405E-05

Temperatura (C) 0.10185E+03 0.20974E-05

9

Presin (atm) 0.30000E+01 0.00000E+00

Flujo molar A (gmol/h) 0.61579E+03 0.43611E-05

Flujo molar B (gmol/h) 0.17382E+04 0.36519E-05

Flujo molar C (gmol/h) 0.23684E+03 0.83110E-05

10

Entalpa (cal/gmol) 0.98329E+06 0.62291E-05

Flujo molar total (gmol/h) 0.25908E+04 0.42405E-05

Temperatura (C) 0.15000E+03 0.00000E+00

Presin (atm) 0.30000E+01 0.00000E+00

Flujo molar A (gmol/h) 0.61579E+03 0.43611E-05

Flujo molar B (gmol/h) 0.17382E+04 0.36519E-05

Flujo molar C (gmol/h) 0.23684E+03 0.83110E-05

12

Entalpa (cal/gmol) 0.76974E+06 0.47094E-05

Flujo molar total (gmol/h) 0.22895E+04 0.28792E-05

Temperatura (C) 0.15000E+03 0.10173E-06

Presin (atm) 0.30000E+01 0.00000E+00

Flujo molar A (gmol/h) 0.78947E+03 0.20874E-05

Flujo molar B (gmol/h) 0.13579E+04 0.27868E-05

Flujo molar C (gmol/h) 0.14210E+03 0.82680E-05

13

Entalpa (cal/gmol) 0.73189E+06 0.83687E-05

Flujo molar total (gmol/h) 0.13158E+04 0.82569E-05

Temperatura (C) 0.15000E+03 0.10173E-06

Presin (atm) 0.30000E+01 0.00000E+00

Flujo molar A (gmol/h) 0.31579E+03 0.84076E-05

Flujo molar B (gmol/h) 0.76316E+03 0.83176E-05

Flujo molar C (gmol/h) 0.23684E+03 0.83110E-05

En la Tabla 6 se encuentran los archivos DATOS.txt con las modificaciones

respectivas de cada caso.

Tabla 6. Estructuras de los archivos DATOS.txt correspondientes a cada caso en

particular.

Corriente 6 Corriente 9

ASIGNACION 1

1,1,1,1,1,1,0,0,0,0

0

9,3

7,8,1,4,2,5,3,6,9

15

1,7,7,7,1,2,7,7,7,7

3,7,7,1,3

3

1.,3.05E5,1000.,100.,3.

1000.,0.,0.

5.,2.46E5,1500.,25.,1.

0.,1500.,0.

14.,1.06E6,1000.,150.,3.5

0.,550.,450.

9

7.,1.,19.,0.,0.

1.,5.,0.,0.,0.

2.,6.,7.,0.,0.

0.5,0.5,0.,0.

8.,5.,16.,0.,0.

1.,7.,0.,0.,0.

1.,8.,0.,0.,0.

3.

1.,2.,33.,0.,0.

2.,1.,8.,0.,0.

2.,2.,4.,0.,0.

0.70,0.30,0.,0.,0.

ASIGNACION 1

1,1,1,1,1,1,0,0,0,0

0

9,3

7,8,1,4,2,5,3,6,9

15

1,7,7,7,1,7,7,7,2,7

3,7,7,1,3

3

1.,3.05E5,1000.,100.,3.

1000.,0.,0.

5.,2.46E5,1500.,25.,1.

0.,1500.,0.

14.,1.06E6,1000.,150.,3.5

0.,550.,450.

9

7.,1.,19.,0.,0.

1.,5.,0.,0.,0.

2.,6.,7.,0.,0.

0.5,0.5,0.,0.

8.,5.,16.,0.,0.

1.,7.,0.,0.,0.

1.,8.,0.,0.,0.

3.

1.,2.,33.,0.,0.

2.,1.,8.,0.,0.

2.,2.,4.,0.,0.

0.70,0.30,0.,0.,0.

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

4.,2.,33.,0.,0.

3.,4.,6.,13.,0.

1.,9.,0.,0.,0.

1.,0.,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

2.,4.,16.,0.,0.

1.,2.,0.,0.,0.

1.,3.,0.,0.,0.

150.

5.,4.,16.,0.,0.

1.,9.,0.,0.,0.

1.,10.,0.,0.,0.

150.

3.,2.,33.,0.,0.

2.,3.,10.,0.,0.

2.,11.,12.,0.,0.

0.40,0.60,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

6.,2.,33.,0.,0.

2.,12.,14.,0.,0.

2.,13.,15.,0.,0.

0.40,0.60,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

4.,2.,33.,0.,0.

3.,4.,6.,13.,0.

1.,9.,0.,0.,0.

1.,0.,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

2.,4.,16.,0.,0.

1.,2.,0.,0.,0.

1.,3.,0.,0.,0.

150.

5.,4.,16.,0.,0.

1.,9.,0.,0.,0.

1.,10.,0.,0.,0.

150.

3.,2.,33.,0.,0.

2.,3.,10.,0.,0.

2.,11.,12.,0.,0.

0.40,0.60,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

6.,2.,33.,0.,0.

2.,12.,14.,0.,0.

2.,13.,15.,0.,0.

0.40,0.60,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

9.,8.,28.,0.,1.

0.,0.,0.,0.,0.

0.,0.,0.,0.,0.

8.,100.,6.,0.00001,1.

1.,0.,0.,0.,0.

0.,0.,0.

25.5,0.818E-2,0.031E-4

9.,8.,28.,0.,1.

0.,0.,0.,0.,0.

0.,0.,0.,0.,0.

8.,100.,9.,0.00001,1.

1.,0.,0.,0.,0.

0.,0.,0.

Tabla 6. Estructuras de los archivos DATOS.txt correspondientes a cada caso en

particular (Continuacin).

Corriente 10 Corriente 12

ASIGNACION 1

1,1,1,1,1,1,0,0,0,0

0

9,3

7,8,1,4,2,5,3,6,9

15

1,7,7,7,1,7,7,7,7,2

3,7,7,1,3

3

1.,3.05E5,1000.,100.,3.

1000.,0.,0.

5.,2.46E5,1500.,25.,1.

0.,1500.,0.

14.,1.06E6,1000.,150.,3.5

0.,550.,450.

9

7.,1.,19.,0.,0.

1.,5.,0.,0.,0.

2.,6.,7.,0.,0.

0.5,0.5,0.,0.

ASIGNACION 1

1,1,1,1,1,1,0,0,0,0

0

9,3

7,8,1,4,2,5,3,6,9

15

1,7,7,7,1,7,7,7,7,7

3,2,7,1,3

3

1.,3.05E5,1000.,100.,3.

1000.,0.,0.

5.,2.46E5,1500.,25.,1.

0.,1500.,0.

14.,1.06E6,1000.,150.,3.5

0.,550.,450.

9

7.,1.,19.,0.,0.

1.,5.,0.,0.,0.

2.,6.,7.,0.,0.

0.5,0.5,0.,0.

8.,5.,16.,0.,0.

1.,7.,0.,0.,0.

1.,8.,0.,0.,0.

3.

1.,2.,33.,0.,0.

2.,1.,8.,0.,0.

2.,2.,4.,0.,0.

0.70,0.30,0.,0.,0.

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

4.,2.,33.,0.,0.

3.,4.,6.,13.,0.

1.,9.,0.,0.,0.

1.,0.,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

2.,4.,16.,0.,0.

1.,2.,0.,0.,0.

1.,3.,0.,0.,0.

150.

5.,4.,16.,0.,0.

1.,9.,0.,0.,0.

1.,10.,0.,0.,0.

150.

3.,2.,33.,0.,0.

2.,3.,10.,0.,0.

2.,11.,12.,0.,0.

0.40,0.60,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

8.,5.,16.,0.,0.

1.,7.,0.,0.,0.

1.,8.,0.,0.,0.

3.

1.,2.,33.,0.,0.

2.,1.,8.,0.,0.

2.,2.,4.,0.,0.

0.70,0.30,0.,0.,0.

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

4.,2.,33.,0.,0.

3.,4.,6.,13.,0.

1.,9.,0.,0.,0.

1.,0.,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

2.,4.,16.,0.,0.

1.,2.,0.,0.,0.

1.,3.,0.,0.,0.

150.

5.,4.,16.,0.,0.

1.,9.,0.,0.,0.

1.,10.,0.,0.,0.

150.

3.,2.,33.,0.,0.

2.,3.,10.,0.,0.

2.,11.,12.,0.,0.

0.40,0.60,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

6.,2.,33.,0.,0.

2.,12.,14.,0.,0.

2.,13.,15.,0.,0.

0.40,0.60,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

9.,8.,28.,0.,1.

0.,0.,0.,0.,0.

0.,0.,0.,0.,0.

8.,100.,10.,0.00001,1.

1.,0.,0.,0.,0.

0.,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

6.,2.,33.,0.,0.

2.,12.,14.,0.,0.

2.,13.,15.,0.,0.

0.40,0.60,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

9.,8.,28.,0.,1.

0.,0.,0.,0.,0.

0.,0.,0.,0.,0.

8.,100.,12.,0.00001,1.

1.,0.,0.,0.,0.

0.,0.,0.

4. Utilice la secuencia de clculo adecuada que permita observar la influencia de

suponer el valor inicial de la corriente 13.

Al modificar la estructura original, aadiendo como conocida la corriente 13, y

ejecutar SIMEST.exe, pudo observarse que esta corriente tom sus valores correspondientes

a la respuesta del sistema en caso anteriores, lo cual indica que establecerla como conocida,

no influye en los resultados obtenidos al final ya que esta forma parte de un reciclo, por lo

que naturalmente toma su valor correspondiente acorde a la dinmica del sistema. La

estructura del archivo DATOS.txt, se encuentra en la Tabla 7.

Tabla 7. Estructuras de los archivos DATOS.txt correspondientes a cada caso en

particular.

Corriente 13 desconocida Corriente 13 conocida

ASIGNACION 1

1,1,1,1,1,1,0,0,0,0

0

9,3

7,8,1,4,2,5,3,6,9

15

1,7,7,7,1,7,7,7,7,7

3,7,2,1,3

3

1.,3.05E5,1000.,100.,3.

1000.,0.,0.

5.,2.46E5,1500.,25.,1.

0.,1500.,0.

14.,1.06E6,1000.,150.,3.5

0.,550.,450.

9

7.,1.,19.,0.,0.

1.,5.,0.,0.,0.

2.,6.,7.,0.,0.

0.5,0.5,0.,0.

8.,5.,16.,0.,0.

1.,7.,0.,0.,0.

1.,8.,0.,0.,0.

3.

1.,2.,33.,0.,0.

2.,1.,8.,0.,0.

2.,2.,4.,0.,0.

0.70,0.30,0.,0.,0.

ASIGNACION 1

1,1,1,1,1,1,0,0,0,0

0

9,3

7,8,1,4,2,5,3,6,9

15

1,7,7,7,1,7,7,7,7,7

3,7,2,1,3

4

1.,3.05E5,1000.,100.,3.

1000.,0.,0.

5.,2.46E5,1500.,25.,1.

0.,1500.,0.

13.,2,14E6,3846.,98.,3.

923.,2231.,692.

14.,1.06E6,1000.,150.,3.5

0.,550.,450.

9

7.,1.,19.,0.,0.

1.,5.,0.,0.,0.

2.,6.,7.,0.,0.

0.5,0.5,0.,0.

8.,5.,16.,0.,0.

1.,7.,0.,0.,0.

1.,8.,0.,0.,0.

3.

1.,2.,33.,0.,0.

2.,1.,8.,0.,0.

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

4.,2.,33.,0.,0.

3.,4.,6.,13.,0.

1.,9.,0.,0.,0.

1.,0.,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

2.,4.,16.,0.,0.

1.,2.,0.,0.,0.

1.,3.,0.,0.,0.

150.

5.,4.,16.,0.,0.

1.,9.,0.,0.,0.

1.,10.,0.,0.,0.

150.

3.,2.,33.,0.,0.

2.,3.,10.,0.,0.

2.,11.,12.,0.,0.

0.40,0.60,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

6.,2.,33.,0.,0.

2.,12.,14.,0.,0.

2.,13.,15.,0.,0.

0.40,0.60,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

2.,2.,4.,0.,0.

0.70,0.30,0.,0.,0.

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

4.,2.,33.,0.,0.

3.,4.,6.,13.,0.

1.,9.,0.,0.,0.

1.,0.,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

2.,4.,16.,0.,0.

1.,2.,0.,0.,0.

1.,3.,0.,0.,0.

150.

5.,4.,16.,0.,0.

1.,9.,0.,0.,0.

1.,10.,0.,0.,0.

150.

3.,2.,33.,0.,0.

2.,3.,10.,0.,0.

2.,11.,12.,0.,0.

0.40,0.60,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

6.,2.,33.,0.,0.

2.,12.,14.,0.,0.

2.,13.,15.,0.,0.

0.40,0.60,0.,0.,0

25.5,0.818E-2,0.031E-4

9.,8.,28.,0.,1.

0.,0.,0.,0.,0.

0.,0.,0.,0.,0.

8.,100.,13.,0.00001,1.

1.,0.,0.,0.,0.

0.,0.,0.

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

9.,8.,28.,0.,1.

0.,0.,0.,0.,0.

0.,0.,0.,0.,0.

8.,100.,13.,0.00001,1.

1.,0.,0.,0.,0.

0.,0.,0.

5. Cul es la influencia al variar la fraccin de separacin en la corriente 13 sobre

el proceso iterativo?

Al variar la fraccin de separacin, pudo observarse que a medida que se aumentaba esta,

proporcionalmente aumentaba el nmero de iteraciones. Esto se debe a que a medida que la

corriente 13 forma parte de un reciclo, y al aumentar su magnitud influye de manera

significativa en la respuesta del sistema. La variacin del nmero de iteraciones en funcin

de la fraccin de separacin se encuentra en la Tabla 8.

Tabla 8. La variacin del nmero de iteraciones en funcin de la fraccin de

separacin en la corriente 13.

Fraccin de separacin Nmero de iteraciones

0,1 6

0,2 7

0,3 8

0,4 8

0,5 11

0,6 12

0,7 14

0,8 16

0,9 19

6. Cul es la variable de la corriente a vigilar que el controlador utiliza para

realizar los clculos de criterio mximo fraccional?, sta se mantiene para todas

las iteraciones?

El controlador toma en cuenta todas las variables correspondientes de la corriente que

vigila, evaluando para cada una tolerancia de desviacin con respecto al criterio fraccional

establecido por el usuario. La convergencia se alcanza cuando todas las variables han

alcanzado una fraccin de error por debajo de la establecida por el usuario.

7. Utilice la convergencia acelerada, determine la influencia de Beta al utilizar el

promotor de convergencia 1 y compare los resultados al utilizar el promotor de

convergencia 2.

Al utilizar el promotor de convergencia CONV1, con un valor de igual a 2, se

obtuvieron un nmero mayor de iteraciones (14 iteraciones) que sin hacer uso de este (I9

iteraciones), lo cual demuestra que para este caso no es conveniente este tipo de promotor.

Por el contrario, al usar el promotor CONV2, se logr alcanzar la convergencia del sistema

con un nmero de iteraciones menor al original (5 iteraciones), por lo que resulta muy

conveniente y efectiva su utilizacin para la simulacin de este proceso. En la Tabla 9 se

ubica la estructura del archivo DATOS.txt para cada promotor de convergencia.

Tabla 9. Estructuras de los archivos DATOS.txt correspondientes a cada caso en

particular.

CONV1 CONV2

ASIGNACION 1

1,1,1,1,1,1,0,0,0,0

0

10,3

7,8,1,4,2,5,3,6,10,9

16

1,7,7,7,1,7,7,7,7,7

ASIGNACION 1

1,1,1,1,1,1,0,0,0,0

0

10,3

7,8,1,4,2,5,3,6,10,9

16

1,7,7,7,1,7,7,7,7,7

3,7,2,1,3,7

3

1.,3.05E5,1000.,100.,3.

1000.,0.,0.

5.,2.46E5,1500.,25.,1.

0.,1500.,0.

14.,1.06E6,1000.,150.,3.5

0.,550.,450.

10

7.,1.,19.,0.,0.

1.,5.,0.,0.,0.

2.,6.,7.,0.,0.

0.5,0.5,0.,0.

8.,5.,16.,0.,0.

1.,7.,0.,0.,0.

1.,8.,0.,0.,0.

3.

1.,2.,33.,0.,0.

2.,1.,8.,0.,0.

2.,2.,4.,0.,0.

0.70,0.30,0.,0.,0.

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

4.,2.,33.,0.,0.

3.,4.,6.,16.,0.

1.,9.,0.,0.,0.

1.,0.,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

3,7,2,1,3,7

3

1.,3.05E5,1000.,100.,3.

1000.,0.,0.

5.,2.46E5,1500.,25.,1.

0.,1500.,0.

14.,1.06E6,1000.,150.,3.5

0.,550.,450.

10

7.,1.,19.,0.,0.

1.,5.,0.,0.,0.

2.,6.,7.,0.,0.

0.5,0.5,0.,0.

8.,5.,16.,0.,0.

1.,7.,0.,0.,0.

1.,8.,0.,0.,0.

3.

1.,2.,33.,0.,0.

2.,1.,8.,0.,0.

2.,2.,4.,0.,0.

0.70,0.30,0.,0.,0.

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

4.,2.,33.,0.,0.

3.,4.,6.,16.,0.

1.,9.,0.,0.,0.

1.,0.,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

2.,4.,16.,0.,0.

1.,2.,0.,0.,0.

1.,3.,0.,0.,0.

150.

5.,4.,16.,0.,0.

1.,9.,0.,0.,0.

1.,10.,0.,0.,0.

150.

3.,2.,33.,0.,0.

2.,3.,10.,0.,0.

2.,11.,12.,0.,0.

0.40,0.60,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

6.,2.,33.,0.,0.

2.,12.,14.,0.,0.

2.,13.,15.,0.,0.

0.40,0.60,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

10.,6.,34.,0.,0.

1.,13.,0.,0.,0.

1.,16.,0.,0.,0.

2.,0.,0.,0.,0.

0.,0.,0.,0.,0.

0.,0.,2.,2.,2.

2.,2.,2.,2.

9.,8.,28.,0.,1.

0.,0.,0.,0.,0.

2.,4.,16.,0.,0.

1.,2.,0.,0.,0.

1.,3.,0.,0.,0.

150.

5.,4.,16.,0.,0.

1.,9.,0.,0.,0.

1.,10.,0.,0.,0.

150.

3.,2.,33.,0.,0.

2.,3.,10.,0.,0.

2.,11.,12.,0.,0.

0.40,0.60,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

6.,2.,33.,0.,0.

2.,12.,14.,0.,0.

2.,13.,15.,0.,0.

0.40,0.60,0.,0.,0

31.15,-1.34E-2,0.1197E-4,0.,0.

19.25,-0.0003E-2,0.1746E-4,0.,0.

25.5,0.818E-2,0.031E-4

10.,7.,34.,0.,0.

1.,13.,0.,0.,0.

1.,16.,0.,0.,0.

3.,0.,0.,0.,0.

0.,0.,0.,0.,0.

0.,0.,0.,0.,0.

0.,0.,0.,0.

9.,8.,28.,0.,1.

0.,0.,0.,0.,0.

0.,0.,0.,0.,0.

9.,100.,13.,0.00001,1.

1.,0.,0.,0.,0.

0.,0.,0.

0.,0.,0.,0.,0.

9.,100.,13.,0.00001,1.

1.,0.,0.,0.,0.

0.,0.,0.

8. Es posible lograr la simulacin correcta y completa del sistema al indicar que

el controlador solo controla a 4 unidades?, de ser afirmativo indique cuales son

los cambios que se debieron efectuar para lograrlo.

Al indicar que el controlador, valga la redundancia, controle nicamente 4 unidades,

no se obtiene una simulacin efectiva y completa, slo se realizan 3 iteraciones, y los

resultados finales de los parmetros de la corriente que vigila, no varan de los iniciales. Por

lo que no se recomienda este tipo de modificacin, debido a que se obtienen resultados

incorrectos e incompletos.