2 1 unjbg
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2. Para el circuito de la figura: a) hallar las corrientes I 1 , I 2 , I3 , I 4 e I 5 . b) determinar los voltajes V ab yV bc.
Solucióna) Hallando I1
Aplicando la ley de ohmV=IR
I=VR
=12040
=3 A
I 1=3 A
b) Hallando I2
Resistencia den serieReq=R1+R2+R3
Req=15+5+20
Req=40Ω
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Req=10∗4010+40
Req=8Ω
Aplicando la ley de ohm
V=IR
I 2=VR
I 2=120
26+8
I 2=3.529 A
c) Aplicando divisor de corrienteI 3=
I 2 (15+5+10 )(10+5+15 )+10
I 3=2.8232 A
I 4=I 2−I 3=3.529−2.8232
I 4=0.7054 A
Hallando I 5
Aplicando la ley de ohmV=IR
I=VR
I 5=120
24+30+20
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I 5=1.6216 A
Hallando Vab= ¿?V ab=−24 I5+26 I 2+15 I 4
V ab=−24 (1.6216 )+26 (3.529 )+15 (0.7054 )
V ab=63.4166 v
Hallando Vbc= ¿?V bc=−26 I 2−15 I 4
V cb=−26 (3.529 )−15 (0.7054 )
V cb=−102.335v